compiler: fix double evaluation with interface field expression

In Interface_field_reference_expression, the interface expression
    is used in two places, so a temporary variable is used. Previously,
    we used a Set_and_use_temporary_expression, which, when evaluated
    twice, causes double evaluation of the underlying expression. Fix
    by setting the temporary once and use Temporary_reference_expression
    instead.
    
    Fixes golang/go#26248.
    
    Reviewed-on: https://go-review.googlesource.com/122756

From-SVN: r262533
This commit is contained in:
Ian Lance Taylor 2018-07-10 00:55:28 +00:00
parent fd7ec17d0b
commit c0cb9a9da0
2 changed files with 3 additions and 4 deletions

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@ -1,4 +1,4 @@
94738979a3422e845acf358a766aabf8b9275d43
8ad67a72a4fa59efffc891e73ecf10020e3c565d
The first line of this file holds the git revision number of the last
merge done from the gofrontend repository.

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@ -11886,10 +11886,9 @@ Interface_field_reference_expression::do_flatten(Gogo*, Named_object*,
if (!this->expr_->is_variable())
{
Temporary_statement* temp =
Statement::make_temporary(this->expr_->type(), NULL, this->location());
Statement::make_temporary(NULL, this->expr_, this->location());
inserter->insert(temp);
this->expr_ = Expression::make_set_and_use_temporary(temp, this->expr_,
this->location());
this->expr_ = Expression::make_temporary_reference(temp, this->location());
}
return this;
}