Fix typos in the manual and in a comment
* lisp/minibuffer.el (completion-pcm--hilit-commonality): * doc/lispintro/emacs-lisp-intro.texi (Mode Line): Fix typos (bug#51434). Copyright-paperwork-exempt: yes
This commit is contained in:
parent
bea843dee1
commit
d72fefdeab
2 changed files with 8 additions and 7 deletions
|
@ -17843,7 +17843,7 @@ xmodmap -e "keysym Alt_L = Meta_L Alt_L"
|
||||||
Finally, a feature I really like: a modified mode line.
|
Finally, a feature I really like: a modified mode line.
|
||||||
|
|
||||||
When I work over a network, I forget which machine I am using. Also,
|
When I work over a network, I forget which machine I am using. Also,
|
||||||
I tend to I lose track of where I am, and which line point is on.
|
I tend to lose track of where I am, and which line point is on.
|
||||||
|
|
||||||
So I reset my mode line to look like this:
|
So I reset my mode line to look like this:
|
||||||
|
|
||||||
|
|
|
@ -3579,12 +3579,13 @@ between 0 and 1, and with faces `completions-common-part',
|
||||||
;; "hole" in the middle of the string is indicated by
|
;; "hole" in the middle of the string is indicated by
|
||||||
;; "-". Note that there are no "holes" near the edges
|
;; "-". Note that there are no "holes" near the edges
|
||||||
;; of the string. The completion score is a number
|
;; of the string. The completion score is a number
|
||||||
;; bound by ]0..1]: the higher the better and only a
|
;; bound by (0..1] (i.e., larger than (but not equal
|
||||||
;; perfect match (pattern equals string) will have
|
;; to) zero, and smaller or equal to one): the higher
|
||||||
;; score 1. The formula takes the form of a quotient.
|
;; the better and only a perfect match (pattern equals
|
||||||
;; For the numerator, we use the number of +, i.e. the
|
;; string) will have score 1. The formula takes the
|
||||||
;; length of the pattern. For the denominator, it
|
;; form of a quotient. For the numerator, we use the
|
||||||
;; first computes
|
;; number of +, i.e. the length of the pattern. For
|
||||||
|
;; the denominator, it first computes
|
||||||
;;
|
;;
|
||||||
;; hole_i_contrib = 1 + (Li-1)^(1/tightness)
|
;; hole_i_contrib = 1 + (Li-1)^(1/tightness)
|
||||||
;;
|
;;
|
||||||
|
|
Loading…
Add table
Add a link
Reference in a new issue