Don't define KERBEROS, KERBEROS5, or HESIOD if the user specifies

"without".
This commit is contained in:
Chong Yidong 2007-03-19 01:05:29 +00:00
parent 39e653ead8
commit ae61688f89

View file

@ -54,7 +54,9 @@ AC_DEFINE(MAIL_USE_POP))
AH_TEMPLATE(MAIL_USE_POP, [Define to support POP mail retrieval.])dnl
AC_ARG_WITH(kerberos,
[ --with-kerberos support Kerberos-authenticated POP],
[AC_DEFINE(KERBEROS)])
[if test "$withval" = yes; then
AC_DEFINE(KERBEROS)
fi])
AH_TEMPLATE(KERBEROS,
[Define to support Kerberos-authenticated POP mail retrieval.])dnl
AC_ARG_WITH(kerberos5,
@ -64,11 +66,13 @@ AC_ARG_WITH(kerberos5,
with_kerberos=yes
AC_DEFINE(KERBEROS)
fi
fi
AC_DEFINE(KERBEROS5, 1, [Define to use Kerberos 5 instead of Kerberos 4.])])
AC_DEFINE(KERBEROS5, 1, [Define to use Kerberos 5 instead of Kerberos 4.])
fi])
AC_ARG_WITH(hesiod,
[ --with-hesiod support Hesiod to get the POP server host],
[AC_DEFINE(HESIOD, 1, [Define to support using a Hesiod database to find the POP server.])])
[if test "$withval" = yes; then
AC_DEFINE(HESIOD, 1, [Define to support using a Hesiod database to find the POP server.])
fi])
AC_ARG_WITH(sound,
[ --without-sound don't compile with sound support])